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vekshin1
3 years ago
13

Is it possible to draw an isosceles right triangle with side lengths 5,5,and 10? Explain.

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

no

Step-by-step explanation:

No because 5+5=10 and the triangle cannot have an area.

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Evaluate the difference quotient for the given function.
kherson [118]

Assuming you mean f(t) = g(t) × h(t), notice that

f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)

Then the difference quotient of f is

\dfrac{\frac12 \sin(2(t+h)) - \frac12 \sin(2t)}h = \dfrac{\sin(2t+2h) - \sin(2t)}{2h}

Recall the angle sum identity for sine:

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

Then we can write the difference quotient as

\dfrac{\sin(2t)\cos(2h) + \cos(2t)\sin(2h) - \sin(2t)}{2h}

or

\boxed{\sin(2t)\dfrac{\cos(2h)-1}{2h} + \cos(2t)\dfrac{\sin(2h)}{2h}}

(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)

7 0
3 years ago
Question 1 through 6 . <br> THANKS.
Sergio039 [100]
Remember, these are quadrilaterals, so they must add up to 360°. Just add up the angles and then do 360 minus that number to solve for x. Therefore: 1. 118 + 90 + 99 = 307 360 - 307 = 53 2. 110 + 96 + 78 = 284 360 - 284 = 76 3. 48 + 118 + 97 = 263 360 - 263 = 97 4. 105 + 99 + 64 = 268 360 - 268 = 92 5. 103 + 63 + 113 = 279 360 - 279 = 81 6. 95 + 80 + 88 = 263 360 - 263 = 97
4 0
3 years ago
40% =32/ what is the full fraction
Levart [38]
40% = 32/x

Rewrite using a decimal

.40 = 32 / x

Multiply both sides by x
.40x = 32

Divide both sides by .40
x = 32 / .40
x = 80

Write the full fraction
32/80

Answer 32/80

3 0
3 years ago
2,300+-2,500+3,300+-2,600+6,250
Lorico [155]
1 Simplify

<span><span>2300−2500+3300−2600+6250</span>
2 Simplify

<span><span>6,750

I hope this helps. 

Have a awesome day. :)

</span><span>
</span></span><span>

</span></span>
5 0
4 years ago
Read 2 more answers
Which sequence of transformations produces R’S’T’ from RST?
inn [45]

Answer:

A translation 2 units right and then a reflection over the x-axis

Step-by-step explanation:

The given vertices of ΔRST are R(0, 0), S(-2, 3), and T(-3, 1)

The vertices of triangle ΔR'S'T' are (2, 0), (0, -3), (-1, -1)

The points are plotted with the aid of MS Excel, and by observation, we have that the image of ΔRST is located on the other side of the x-axis with each coordinate on ΔR'S'T' shifted 2 units to the right of ΔRST

A translation of ΔRST 2 units right gives;

(0 + 2, 0) = (2, 0), (-2 + 2, 3) = (0, 3), and (-3 + 2, 1) = (-1, 1), to give;

(2, 0), (0, 3), and (-1, 1)

A reflection of the point (x, y) across the x-axis gives (x, -y)

A reflection of the above points across the x-axis gives;

(2, 0) reflected about x-axis → (2, 0) reflected about x-axis → (0, -3), and (-1, 1)  reflected about x-axis → (-1, -1), which are the points of ΔR'S'T'

Therefore, the sequence of transformations that produces R'S'T' from RST are;

A translation 2 units right and then a reflection over the x-axis

6 0
3 years ago
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