All categories

3 years ago

Select the correct answer.

Mathematics

1 answer:

Basile [38]3 years ago

6 0

Answer:

(3,0), (4,0), (5,0)

on the x-axis at 3, 4 and 5

Step-by-step explanation:

This function is a lovely swoopey cubic curve. If we finish factoring it, it's not to hard to see the x-intercepts. You set it equal to zero and solve it. The solutions are the x-intercepts (are the "zeros")

0=(x-5)(x^2-7x+12)

0=(x-5)(x-3)(x-4)

0=x-5, 0=x-3 & 0=x-4

x=5, x=3, x=4

This is where the graph crosses the x-axis.

You might be interested in

Please help me with this question? i’d appreciate it :)

UNO [17]

Answer:

1.2

Step-by-step explanation:

Output of f, which also means f(x), when x = -6 is 1.2.

Using the graph given, this implies that, when x = -6, the corresponding value of f(x) will give us 1.2.

Thus:

f(-6) = 1.2 =>> (-6, 1.2).

5 0

3 years ago

Convert the following base 10 numbers to the respective base indicated .

Veseljchak [2.6K]

21 to base 2 is 10101

109 to base 4 is 1231

1652 to base 9 is 2235

5 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

4 years ago

Whoever gets this correct gets brain, 5 stars and a thanks! An explanation of it would be amazing! Tysm!

vlabodo [156]

Answer:

C and E and F

Step-by-step explanation:

Integers are basically whole numbers. For example, 6.5 is not an integer since it is not a whole number and it is between 6 and 7. Also fractions that cannot be simplified to whole numbers are not integers. Also integers can be negative.

6 0

3 years ago

Please help me in this one!!

olga2289 [7]

A^3
a to the power of three

6 0

3 years ago

Read 2 more answers