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Murljashka [212]

3 years ago

14

Which option correctly replaces the letters X and Y? An x will bind to the Y of an enzyme so that the chemical reaction can occu

r.

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

c

Step-by-step explanation:

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What do we do with the coefficients and exponents when we are multiplying polynomials?

Alina [70]

You have to multiply the coefficient and add the exponents of the variables

5 0

3 years ago

Three times a number is subtracted from another number and the difference is 3. The sum of the two numbers is 31. What is the

Brut [27]

Using the equations y-3x=3 and x+y=31 you can find that x=7 and y=24. There for x is the smaller of the two numbers.

5 0

3 years ago

What is the area<br> of circle <br><br><br><br>with a diameterms of 10 m

pentagon [3]

Answer:

exact area = 25(pi) m^2

approximate area = 78.54 m^2

Step-by-step explanation:

diameter = 10 m

radius = diameter/2 = 10 m / 2 = 5 m

area = (pi)r^2

area = (pi)(5 m)^2

area = 25(pi) m^2

area = 78.54 m^2

6 0

3 years ago

Pls answer and get branily

Dennis_Churaev [7]

Answer:

Just put 4 basketballs and 5 baseballs in each one

Step-by-step explanation:

If you think about it you will know that each ratio there is the same. So, you do the same thing each time.

All you have to do now is read. It says put 4 basketballs and 5 baseballs.

I hope this helped ;)

6 0

3 years ago

What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1

Ratling [72]

Answer:

$\sqrt3$

Step-by-step explanation:

To find:

The value of $tan60^\circ$ = ?

Solution:

Kindly consider the equilateral $\triangle ABC$ as attached in the answer area.

Let the side of triangle = $a$ units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = $\frac{a}{2}$

Using Pythagorean Theorem in $\triangle ABD$ :

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

Side AD = $\frac{\sqrt3}{2}a$

Using Trigonometric ratio:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tanB = \dfrac{AD}{BD}$

Putting the values of AD and BD:

$tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}$

5 0

2 years ago

Read 2 more answers