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3 years ago

5

If O is center of circle and angle CBO is 40° then what are values of angle BCO and

2 answers:

Aleksandr [31]3 years ago

8 0

If any line drawn from center of the circle (OC in the diagram) bisect the chord of circle (AB in the diagram), then it is said to be perpendicular to chord AB.
So OC is perpendicular to CB, and we can say that triangle OCB is the Right Triangle.

In the Right Triangle OCB,
angle BCO = 90°
angle COB = 90° - angle CBO = 90° - 40° = 50°

So, option A is the final answer, 90° and 50°.

Igoryamba3 years ago

8 0

If any line drawn from center of the circle (OC in the diagram) bisect the chord of circle (AB in the diagram), then it is said to be perpendicular to chord AB.

So OC is perpendicular to CB, and we can say that triangle OCB is the Right Triangle.

In the Right Triangle OCB,

angle BCO = 90°

angle COB = 90° - angle CBO = 90° - 40° = 50°

So, option A is the final answer, 90° and 50

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Step-by-step explanation:

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$\begin{array}{cccccccc}83&87&90&92&93&100&104&111\\115&121&&&&&&\end{array}$

we use the following formula

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Step 1: Find the mean $\left( \overline{X} \right)$ .

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}$

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Step 2: Create the below table.

Step 3: Find the sum of numbers in the last column to get.

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Step 4: Calculate σ using the above formula.

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