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belka [17]
2 years ago
10

3(9-8x-4x)+8(3x+4)=11 how do I work this out???

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
7 0
Remember PEMDAS is the order of operations. parenthesis,exponents,multiply,divide,add,subtract. so -8x-4x is -12x. now simplified the problem is 3(9-12x) + 8(3x+4)=11 . now I would distribute the numbers before the parentheses and it becomes 27-36x + 24x+32 =11 . now combine like terms. 59-12x =11 . subtract 59 on both sides. -12x=-48. divide -12 on both sides. x=4. :-)
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Can someone please help me with # 2 #13 thanks show work how it's done, please
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Problem 13

10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get

10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q

so we get the original expression again. Here 10 is the GCF of the two terms.

--------------------------------------------------------------

Plug p = 1 and q = 2 into the factored form

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As a check, let's plug those p,q values into the original expression

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