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belka [17]
3 years ago
10

3(9-8x-4x)+8(3x+4)=11 how do I work this out???

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0
Remember PEMDAS is the order of operations. parenthesis,exponents,multiply,divide,add,subtract. so -8x-4x is -12x. now simplified the problem is 3(9-12x) + 8(3x+4)=11 . now I would distribute the numbers before the parentheses and it becomes 27-36x + 24x+32 =11 . now combine like terms. 59-12x =11 . subtract 59 on both sides. -12x=-48. divide -12 on both sides. x=4. :-)
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Step-by-step explanation:

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The point-slope form of the equation of line that passes through points (8, 4) and (0, 2) is y - 4 = 1/4(x -8). What is
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Step-by-step explanation:

The slope-intercept form of the equation for a line can be found by solving the given equation for y. It can be written directly from the slope and the y-intercept.

<h3>Solve for y</h3>

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<h3>Use given information</h3>

Alternatively, you can use the given information to write the slope-intercept equation directly. The slope in the point-slope form is the multiplier outside parentheses. In y-4 = 1/4(x -8), the slope is 1/4.

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2 years ago
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4 0
3 years ago
A random sample of n1 = 296 voters registered in the state of California showed that 146 voted in the last general election. A r
stiv31 [10]

Answer:

The p-value of the test is 0.0139 < 0.05, which means that these data indicates that the population proportion of voter turnout in Colorado is higher than that in California.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

California:

Sample of 296 voters, 146 voted. This means that:

p_{Ca} = \frac{146}{296} = 0.4932

s_{Ca} = \sqrt{\frac{0.4932*0.5068}{296}} = 0.0291

Colorado:

Sample of 215 voters, 127 voted. This means that:

p_{Co} = \frac{127}{215} = 0.5907

s_{Co} = \sqrt{\frac{0.5907*0.4093}{215}} = 0.0335

Test if the population proportion of voter turnout in Colorado is higher than that in California:

At the null hypothesis, we test if it is not higher, that is, the subtraction of the proportions is at most 0. So

H_0: p_{Co} - p_{Ca} \leq 0

At the alternative hypothesis, we test if it is higher, that is, the subtraction of the proportions is greater than 0. So

H_1: p_{Co} - p_{Ca} > 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = p_{Co} - p_{Ca} = 0.5907 - 0.4932 =  0.0975

s = \sqrt{s_{Co}^2+s_{Ca}^2} = \sqrt{0.0291^2+0.0335^2} = 0.0444

Value of the test statistic:

z = \frac{X - \mu}{s}

z = \frac{0.0975 - 0}{0.0444}

z = 2.2

P-value of the test and decision:

The p-value of the test is the probability of finding a difference above 0.0975, which is 1 subtracted by the p-value of z = 2.2.

Looking at the z-table, z = 2.2 has a p-value of 0.9861.

1 - 0.9861 = 0.0139.

The p-value of the test is 0.0139 < 0.05, which means that these data indicates that the population proportion of voter turnout in Colorado is higher than that in California.

3 0
3 years ago
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