Answer:
The square root of a prime number is always an irrational number, then the product of the square root of a prime number and a nonzero rational number is equivalent to:
"the product of an irrational number and a rational number different than zero...."
We know that the product of an irrational number and a rational number (different than zero) is ALWAYS an irrational number.
Then "When is the product of the square root of a prime number and a nonzero rational number a rational number?"
Never, the product will always be irrational.
First you have to rewrite the equation:
(x ÷ 4) + 8 = 38
Second you have to write the division as fraction:
(¼x) + 8 = 38
Third you have to take off the unecessary bracket:
¼x + 8 = 38
Fourth multiply 8 and 38 by 4
x + 32 = 152
Fifth step move the constant to the right hand and change the sign.
x = 152 - 32
Then subtract:
x = 120
Hope this helps :))
<h3>hello!</h3>
let's evaluate this expression




Multiply:

Final Step:-


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<h3>note:-</h3>
Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)
1) 8 + 4 = -5 + 7
12 = 2
FALSE
2) y = -11x + 4
(0, -7): -7 = -11(0) + 4 ⇒ -7 = 0 + 4 ⇒ -7 = 4 False
(-1, -7): -7 = -11(-1) + 4 ⇒ -7 = 11 + 4 ⇒ -7 = 15 False
(1, -7): -7 = -11(1) + 4 ⇒ -7 = -11 + 4 ⇒ -7 = -7 True
(2, 26): 26 = -11(2) + 4 ⇒ 26 = -22 + 4 ⇒ 26 = -18 False
Answer: C
3) Input Output
0 0
<u> 1 </u> 3
2 <u> 6 </u>
3 9
<u> 4 </u> <u> 12 </u>
5 15
6 <u> 18 </u>
Rule: input is being added by 1, output is 3 times x
4) c = 65h
5) 2x = -6

x = -3
6) 8j - 5 + j = 67
9j - 5 = 67 <em>added like terms (8j + j)</em>
<u> +5</u> <u>+5 </u>
9j = 72

j = 8
7) y = mx + b
<u> -b</u> <u> -b </u>
y - b = mx


Answer:
296
Step-by-step explanation: