1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
chubhunter [2.5K]
3 years ago
10

A Circle has a diameter of 9 cm. Find the Circumference. Give a Simplified Exact answer. Enter pi with answer. For example 4pi

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
8 0
First, find the radius of the circle. 
-The radius of a circle is half the length of the diameter. If r=radius and d=diameter it would be r=d/2. The radius of the circle is r=9/2=4.5. So the radius of the circle is 4.5 cm. 

Second, use the circumference equation of a circle to find the circumference. 
The equation is C=2\pir, where C=circumference and r=radius. Then plug in your numbers. 
C=2\pi4.5=9\pi

So the answer is 9\pi cm. 
lutik1710 [3]3 years ago
3 0
Circumference = Diameter * \pi

So 9\pi is the answer
You might be interested in
Tan(θ)/sec(θ) − cos(θ)
myrzilka [38]
Sin(theta)- cos(theta)
4 0
3 years ago
An experiment started with 100 bacteria. They double in number every hour. Find the number of bacteria after 8 hours.
zzz [600]
There will be 25,6000
8 0
3 years ago
Ron and Freddy built structures out of snap cubes. Ron's tower had an 8-inch square base. Freddy had a 6-inch square base. If Ro
Sphinxa [80]

Answer: Ron tower's

Step-by-step explanation:

Given

Ron tower has a base of A_r=8\ in.^2

Freddy tower has a base of A_f=6\ in.^2

Suppose the tower is in the shape of a square prism

The volume of Ron and Freddy tower is 320\ \text{and}\ 180\ in.^3

The volume of a square-based prism is  V=\frac{1}{3}a^2h

\therefore \text{height of Ron tower is}\ h_r=\dfrac{3V}{A_r}\\\\\Rightarrow h_r=\dfrac{3\times 320}{8}=120\ in.

The height of Freddy tower is

\Rightarrow h_f=\dfrac{3V}{A_f}\\\\\Rightarrow h_f=\dfrac{3\times 180}{6}=90\ in.

Thus, the height of Ron's tower is  more than Freddy's tower by 30\ in.

6 0
2 years ago
A blue container weighs 4 x 103
NemiM [27]

Answer:

208

Step-by-step explanation:

First let's find out what each container weighs..

Blue = 4 x 103 = 412

Red = 102 x 2 = 204

Now, Let subtract Blue container by Red Container..

412-204=208

Hence, the blue container weighs 208 more than the red container.

8 0
2 years ago
Can someone please help me please !
TEA [102]

Answer:

Step-by-step explanation:

GH : √(8-4)^2 + (2-5)^2 = √16+9 = √25 = 5

HI : √(-6-2)^2 + (2-8)^2 = √64+36 = √100 = 10

IJ : √(-2-2)^2 + (-3+6)^2 = √16 + 9 = √25 = 5

JH : √(-2-4)^2 + (-3-5)^2 = √36 + 64 = √100 = 10

Slope of the line that contains GH

(2-5)/(8-4) = -3/4

Slope of the line that contains HI

(-6-2) / (2-8) = 8/6 = 4/3

I calculated the distance between points. Thanks to that I noticed that the opposite sides are congruent, so the quadrilateral can be a rectangle or a parallelogram. So I found the slope of the lines that contain two consecutive sides and I discovered that are perpendicular. So the quadrilateral is a rectangle because its angles are all of 90 degrees

5 0
3 years ago
Other questions:
  • Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively
    15·2 answers
  • What is the factorization?
    7·1 answer
  • Find an equation of the line with x-intercept 8 and y-intercept 4
    10·2 answers
  • 2x+x(x+6)<br> Solve to the lowest equation/number
    12·2 answers
  • Can someone please help with these 3 I am so confused on what to do thank you!!!!
    7·1 answer
  • Whats the slope of the graph hurry !
    8·2 answers
  • Here’s a picture of it
    10·1 answer
  • Please help me please
    15·1 answer
  • Filomena applies the commutative property to the product. (7/15)⋅(−11)⋅(30) Which expression illustrates the commutative propert
    15·2 answers
  • Someone pls help me with this I will make you brain
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!