Answer:
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
Step-by-step explanation:
We have three conditions
(1) 5P = 3S
(2) S = C + 0.30
(3) P = C – 0.20 Substitute (3) into (1)
=====
(4) 5(C – 0.20) = 3S Substitute (2) into (4)
5(C – 0.20) = 3(C + 0.30) Remove parentheses
5C – 1.00 = 3C + 0.90 Add 1.00 to each side
5C = 3C + 1.90 Subtract 3C from each side
2C = 1.90 Divide each side by 2
C = $0.95 Substitute C into Equation (2)
=====
S = 0.95 + 0.30
S = $1.25 Substitute C into Equation (3)
=====
P = 0.95 – 0.20
P = $0.75
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
There is a theorem that states that RT =2TH.
3x - 7 = 2(x + 1)
3x - 7 = 2x + 2
x - 7 = 2
x = 9
<span>4w^3−8w+12 = 4 (w^3 - 2w + 3)
</span><span>5t^2+20t+50 = 5 (t^2 + 4t + 10)</span>
1/6, 2/3, 3/4 is the answer
