Question

Please help ​What is the equation of a line with a slope of ​ ​ −4 ​ ​ and a point ​ (−2, 5) ​ on the line?

Answer 1

Answer:

all is work is shown and pictured

Answer 2

The point-slope form:

$y-y_1=m(x-x_1)$

We have m = -4 and the point (-2, 5). Substitute:

$y-5=-4(x-(-2))$

$y-5=-4(x+2)$      use distributive property

$y-5=(-4)(x)+(-4)(2)$

$y-5=-4x-8$      add 5 to both sides

$\boxed{y=-4x-3}$