3xy
<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>
<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>
<span>y(3y) + y(xy) + (y+1)(3x) </span>
<span>3y^2 + xy^2 + 3xy +3x </span>
<span>cannot simplify further.</span>
Pq
because they constant is the multiple of the last digit of each factor
Answer:
(x , y) ----> (-x , y)
Step-by-step explanation:
(x , y) ----> (-x , y)
Example for 1. :
(-4,2) ---> (4,2)
Bob cannot distribute the cups in six equal stacks and not have any left over.
Step-by-step explanation:
In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.
So
Dividing 64 by 6

Here
Quotient = 10
Remainder = 4
As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.
Keywords: Division, fractions
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