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ANEK [815]
4 years ago
13

Please help ASAP (multiple choice)

Mathematics
1 answer:
Soloha48 [4]4 years ago
7 0
D neither arithmetic nor geometric
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Andre tried to solve the equation 1/4(x+12)=2 what was his mistake?
GarryVolchara [31]

Step-by-step explanation:

1. 1/4(x + 12)=2 - first isolate X'

         - 12 -12

2. 1/4(x) = -10  - 1/4  since its a fraction, you'll have to subtract not divide

-1/4    - 1/4

3. x = -10.25

Andre did the first step correctly, but on the second step he just divided 1.4 by -10, instead of subtract 1/4 from both sides.

8 0
3 years ago
The hexagon is made from a rectangle and two identical triangles.
satela [25.4K]
I think it’s 12 of the hexagon
7 0
3 years ago
Please help ASAP!!!! 10 points Complete the situate to form a true equation. X^2 -14x+__=(x-__)^2
mylen [45]

Answer:

x^2-14x+49=(x-7)^2

Step-by-step explanation:

This is completing the square

X^2 -14x+__=(x-__)^2

x^2-14x+49=(x-7)^2

-14/2=7

7^2=49

8 0
4 years ago
The sum of a number and 8 is - 30.
kotegsom [21]

Answer:

The number could be -48.

4 0
3 years ago
Read 2 more answers
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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