The area of the surface given by
is 1. In terms of a surface integral, we have

By multiplying each component in
by 5, we have

and the same goes for the derivative with respect to
. Then the area of the surface given by
is

Answer:
137
Step-by-step explanation:
:)
Answer:
23 years.
Step-by-step explanation:
It is given that the initial price of painting is $150 and its values increasing by 3% annually.
We need to find how many years will it take until it is doubled in value.
The value of painting after t years is given by
The value of painting after double is 300. Substitute y=300.
Divide both sides by 150.
Taking log both sides.
Therefore, the required number of years is 23.