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Nezavi [6.7K]
3 years ago
11

Rewrite each expression using each base only once.

Mathematics
1 answer:
mezya [45]3 years ago
8 0
Rewrite each expression using each base only once. 

 (-6)^12 * (-6)^3 * (-6)^2 
 (-6)^(12+3+2)
 (-6)^(17)
 Answer: 
 (-6)^(17)


 2^2 * 2^7 * 2^0 
 (2)^(2+7+0)
 (2)^(9)
 Answer: 
 (2)^(9)

 Simplify each expresion.

 5c^4 * c^6 
 5*c^(4+6)
 5*c^(10)
 Answer:
 5*c^10
 (-2.4n^4)(2n^-1)
 (-2.4*2)(n^4)(n^-1)
 (-2.4*2)(n^(4+(-1))
 (-4.8)(n^(4-1))
 (-4.8)(n^(3))
 Answer: 
 (-4.8)(n^(3))

 (4c^4)(ac^3)(-3a^5c)
 ((4)*(-3))*(c^(4+3+1))*(a^(1+5))
 (-12)*(c^(8))*(a^(6))
 Answer: 
 (-12)*(c^8)*(a^6)

 a^6b^3 * a^2b^-2
 (a^(6+2))*(b^(3+(-2)))
 (a^(8))*(b^(3-2))
 (a^(8))*(b^(1))
 (a^8)*(b)
 Answer: 
 (a^8)*(b)

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Lunna [17]
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HELP QUICK GIVING 50 POINTS!!!
avanturin [10]

Answer:

64/3 cc or 64/3 cm³

Step-by-step explanation:

The formula for the volume of a triangular pyramid is

V = (1/3)(area of base)(height)

Here we have a square prism (actually, a cube), whose square base is 4 cm by 4 cm (4 cm is the cube root of 64 cc).  The height of this cube is also 4 cm.

The volume of a triangular pyramid of base area (4 cm)² and height 4 cm is

V = (1/3)(base area)(height)

   = (1/3)(16 cm²)(4 cm) = 64/3 cc

8 0
3 years ago
fie abc un triunghi cu masura unghiului a de 90 de grade ab este 6 cm bc=10 si ca=8 calculati;sin b; tg b; sin c; tg c; cos b; c
lions [1.4K]
SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
sinC = cosB = AB/ BC = 6/10 = 3/5;
tgC = ctgB = AB/ AC = 6/8 = 3/4.

6 0
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Solve for y: 2y + 3 =11<br><br>Solve for x:<br>2/3x = 18​
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Answer: y=4 x=27

Step-by-step explanation: 2y+3=11

-3 -3

2y=8

/2 /2

y=4

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(3) (3)

2x=54

/2 /2

X=27

5 0
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