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MariettaO [177]
3 years ago
10

Please help picture shpwnn

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0
4/x³ - (2x-1)/3x

= (4*3) - (2x-1)(x²) / 3x³

= (12 - 2x³ - x²) / 3x³

= -2x³ -x² + 12 / 3x³

The answer is C.
Hope it helps!
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2. Which answer shows another way of writing the expression below?
maria [59]

Answer:

  • D. 6b - 2

Step-by-step explanation:

<u>Simplify the expression:</u>

  • 4(3b) – 2(3b + 1) =
  • 12b - 6b - 2 =
  • 6b - 2

Correct choice is D

6 0
3 years ago
Read 2 more answers
Solve each equation for y. Then find the value of y for each value of x. y+3x=8;x=-2,0,2
damaskus [11]
Y=-3x+8
when x=-2:
y=-3(-2)+8
y=6+8
y=14
when x=0
y=-3(0)+8
y=0+8
y=8
when x=2
y=-3(2)+8
y=-6+8
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6 0
3 years ago
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
I need help I would really thank wheeler answers this for me
Agata [3.3K]
The absolute value of a number is however many places a number is away from 0 on a number line.

a. |-15| + |-26|
15 + 26
41

b. -|-40|
-40

c. |0.5| + |-1 1/2|
0.5 + 1 1/2
0.5 = 1/2
1/2 + 1 1/2
2
6 0
3 years ago
Jill’s coach used a computer program to help her improve the distance she can throw a softball. The computer gave a readout of t
Jlenok [28]

Answer:

11.08 feet

Step-by-step explanation: I just got it wrong and it told me the answer. :/

5 0
3 years ago
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