1 year ago

HELP HOW AM I MEANT TO ANSWER THIS QUESTION I WOULD ASO LIKE ANSWER. THX

Mathematics

2 answers:

djverab [1.8K]1 year ago

7 0

6*6= 36
3*3*3*3= 81
2*2*2*2*2= 32
5*5*5= 125
So the answer would be-
2^5,6^2,3^4,5^3

NemiM [27]1 year ago

5 0

Answer: the smallest is 2^5, 6^2, 3^4 and the largest is 5^3

You might be interested in

What is the midpoint of the segment shown below

Artyom0805 [142]

Answer:

wheres the points

Step-by-step explanation:

6 0

2 years ago

Does 2 and 12 have a least common multiple of 24

vova2212 [387]

Answer:

Least common multiple (LCM) of 12 and 24 is 24.

Step-by-step explanation:

6 0

2 years ago

Half x s for s equals 3/10

777dan777 [17]

1/2 x s, where s equals 3/10 means,

(1/2) x (3/10) which will give (3/20)

You simply multiply the numerators to get 3 and the denominators to get 20.

8 0

2 years ago

Kevin is 6 years older than Timothy. 4 years ago, Kevin was twice as old as Timothy. Find their present ages.

Novosadov [1.4K]

Step-by-step explanation:

Hope it helps.

Handwriting is a bit poor. So, restraint is advised!

6 0

2 years ago

1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in

scZoUnD [109]

Answer:

Step-by-step explanation:

a) $\int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

Substitute limits to get

= $\frac{1}{3}$

Thus converges.

b) 10th partial sum =

$\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

= $\frac{-1}{3} (0.001-1)\\= 0.333$

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0

2 years ago