<u>Ans: Mass of NaNO3 = 574 g</u>
<u>Given:</u>
Volume of NaNO3, V = 4.50 L
Molarity of NaNO3, M = 1.50 M i.e. 1.50 moles/L
Molar mass of NaNO3 = 85.00 g/mol
<u>To determine:</u>
The mass of NaNO3
<u>Explanation:</u>
Molarity of a solution can be expressed as the number of moles of the solute in a liter volume of solution
Molarity of NaNO3 = moles of NaNO3/volume of solution in L
1.50 moles/L = moles/4.50 L
moles NaNO3 = 1.50 *4.50 = 6.75 moles
Now, moles of NaNO3 = mass of NaNO3/molar mass NaNO3
mass of NaNO3 = moles * molar mass =
= 6.75 moles * 85.00 g/mole
= 573.75 g = 574 g
Answer:
You would find starch in a plant leaf.
Explanation:
This is due to the fact that when there is excess energy, it will be stored in plant tissue as starch.
Answer:
Explanation:
Radioactive decay follows the equation:
Ln [A] = -kt + ln [A]₀
<em>Where [A] is amount of isotope after time t: Our incognite,</em>
<em>k is rate constant: ln 2 / Half-life = 0.0231 years⁻¹</em>
<em>t are 60 years</em>
<em>[A]₀ is initial amount of isotope: 1.0g</em>
<em />
Replacing:
Ln [A] = -kt + ln [A]₀
Ln [A] = -0.0231 years⁻¹*60 years + ln 1.0g
ln [A] = -1.386
[A] = 0.25g
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Answer: To calculate the pH of HCl you need to know the concentration expressed in molarity (mol HCl/L solution
Explanation:
Answer:
240.17 g Ba3(PO4)2
Explanation:
1. Determine the limiting reactant.
2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
moles H3PO4 = M x V = 3 x 0.286 = .858 moles H3PO4
moles Ba(OH)2 = M x V = 1.4 x 0.855 = 1.197 moles Ba(OH)2
ratio Ba(OH)2 : H3PO4 = 1.197: .858 = 1.39: 1
stoichiometric ratio Ba(OH)2 : H3PO4 = 3:2
Ba(OH)2is the limiting reactant
MM Ba3(PO4)2 = 601.92 g/mol
g Ba3(PO4)2 = moles Ba(OH)2 x(1 mol Ba3(PO4)2/3 moles Ba(OH)2) x (MM Ba3(PO4)2/ 1mol Ba3(PO4)2) = 1.197 x 1/3 x 601.92 = 240.17 g Ba3(PO4)2
