All categories

3 years ago

The chemical reaction in this example is of environmental interest. Iron pyrite (Fesz) is often an impurity in

Chemistry

1 answer:

enot [183]3 years ago

7 0

178.87 grams of sulphur dioxide is formed according to the equation given.

Explanation:

The balanced chemical reaction for the process is:

4 FeS2 + 11 O2 ⇒ 2Fe2O3(-) + 8 SO2

the reaction involving FeS and oxygen having balanced chemical equation as:

moles of oxygen given as 3.84

so when 11 moles of O2 reacts to form 8 moles SO2

3.84 moles of oxygen reacts to form x moles of SO2

$\frac{8}{11}$ = $\frac{x}{3.84}$

x = $\frac{30.72}{11}$

2.792 moles of sulphur dioxide will be formed

The mass can be calculated as number of moles x molar mass of 1 mole of SO2

= 2.792 x 64.066

= 178.87 grams of sulphur dioxide is formed.

You might be interested in

Pentaoxygen monochloride formula

kicyunya [14]

Answer:

Explanation:

O5Cl

6 0

3 years ago

Scientific laws commonly answer which questions about the world?

borishaifa [10]

Answer:

How

Explanation: In science a person has to be curious on how things work. Key word how. Why makes sense but how is the better answer. How many is a specific question. But it doesn't involve the whole spectrum of science. What also doesn't make sense.

4 0

2 years ago

A. amplitude<br> B. frequency<br> C. pitch<br> D. speed

Liono4ka [1.6K]

What is the question!

6 0

3 years ago

Read 2 more answers

ALUMINUM HAS THREE OUTER ELECTRONS Will the element share, gain, or lose electrons when bonding with another element? explain

bearhunter [10]

Answer:

aluminum will lose 3 electrons.

Explanation:

to be stable and losing 3 is easier than gaining 5.

anddd its a metal. :)

7 0

3 years ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has $SP^{2}$ O has $SP^{2}$ .

Explanation : The orbitals of oxygen and carbon which are involved in $SP^{2}$ hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and O also has π orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O $SP^{3}$ H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen $SP^{3}$ hydrogen atoms in it. It has $SP^{3}$ hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c: C is $SP^{3}$ O is also $SP^{3}$

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of $SP^{3}$ hybridized bonds.

Answer 5) Bond d: C atom has $SP^{3}$ C atom has $SP^{3}$

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be $SP^{3}$ . Therefore, the orbitals that undergo $SP^{3}$ hybridization are $SP^{3}$ .

Answer 6) Bond e : C1 containing O $SP^{2}$

C2 is $SP^{3}$

Explanation : The carbon atom which contains oxygen along with a double bond has $SP^{2}$ hybridized orbitals involved in the bonding process; whereas the carbon at C2 has $SP^{3}$ hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0

4 years ago