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AlekseyPX
3 years ago
15

Why rocket science is different from normal science?

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Chemistry
1 answer:
drek231 [11]3 years ago
7 0

Explanation:

rocket \: science \: deals \: with \: designing \\ and \: building \: of \: rocket \\ science \: have \: application \: in \: rocke t \\ science \: i \: guess \: it \: is \: a \: part \:  \\ thank \: you

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Discuss the relationship between amount of energy and the color of light produced by excited electrons
djverab [1.8K]

If you go to this site you should find your answer. http://www.brooklyn.cuny.edu/bc/ahp/LAD/C3/C3_elecEnergy.html


5 0
4 years ago
Two Carnot engines are operated in series with the exhaust (heat output) of the first engine being the input of the second engin
OlgaM077 [116]

Answer:

(a) 140 F

(b) The temperature rise at the point where the heat is dumped is 2.51 degC

Explanation:

(a) Considering T1 the temperature of input of the first engine, T2 the temperature of the exhaust of the first engine (and input of the second engine) and T3 the exhaust of the second engine, if both engines have the same efficiency we have:

\eta=1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}

The temperatures have to be expressed in Rankine (or Kelvin) degrees

1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}\\\\\frac{T_1}{T2}=\frac{T_2}{T_3}\\\\(T_2)^{2} =T_1*T_3\\\\T_2=\sqrt{T_1*T_3} =\sqrt{(459.67+260)*(459.67+40)}= \sqrt{719.67*499.67}\\\\ T_2=599 \, R= (599-459.67) ^{\circ} F=140^{\circ} F

(b) The Carnot efficiency of the cycle is

\eta_{c}=1-Th/Ts=1-(273+20)/(273+315)=0.502

If the efficiency of the plant is 60% of the Carnot efficiency, we have

\eta=0.6*\eta_{c}=0.6*0.502=0.302

The heat used in the plant can be calculated as

Q_i=W/\eta=750MW/0.302=2483MW

And the heat removed to the heat sink is

Q_o=Qi-W=2483-750=1733MW

If the flow of the river is 165 m3/s, the heat per volume in the sink is

\frac{Q_o}{f} =\frac{1733 MJ/s}{165 m3/s}= 10.5MJ/m3

Considering a heat capacity of water C=4.1796 kJ/(kg*K) and a density ρ of 1000 kg/m3, the temperature rise of the water is

\Delta Q=C*\Delta T\\\Delta T=(1/C)*\Delta Q\\\Delta T=(\frac{1}{4.1796\frac{kJ}{kgK} } )*10,500\frac{kJ}{m3}*\frac{1m3}{1000kg}\\\Delta T= 2.51 ^{\circ}C

8 0
4 years ago
Who would most likely be required to work with sodium hydroxide?
maw [93]

Answer:

i think plumber

4 0
4 years ago
Read 2 more answers
Write the electron configuration for Br- and state the number of valence electrons. Select one:
Aleks04 [339]

Answer:

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^62} 4s^{2} 3d^{10} 4p^{5} with 7 valence electrons.

Explanation:

Bromine has 7 unpaired (valence) electrons in its outer shell, and a total of 35 elecrons. Its <em>4s</em> orbital is completely filled with 2 electrons.

The closest answer from the options would be option D.

I hope this helps.

3 0
3 years ago
How many chloride ions are there
Over [174]
Can you show me a picture or a diagram
7 0
3 years ago
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