Given that the molar mass of NaNO3 is 85.00 g/mol, what mass of NaNO3 is needed to make 4.50 L of a 1.50 M NaNO3 solution? Use m

Question

3 years ago

15

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2 answers:

Virty [35] · Answer 1 · 2022-05-18T14:58:57+03:00

Ans: Mass of NaNO3 = 574 g

Given:

Volume of NaNO3, V = 4.50 L

Molarity of NaNO3, M = 1.50 M i.e. 1.50 moles/L

Molar mass of NaNO3 = 85.00 g/mol

To determine:

The mass of NaNO3

Explanation:

Molarity of a solution can be expressed as the number of moles of the solute in a liter volume of solution

Molarity of NaNO3 = moles of NaNO3/volume of solution in L

1.50 moles/L = moles/4.50 L

moles NaNO3 = 1.50 *4.50 = 6.75 moles

Now, moles of NaNO3 = mass of NaNO3/molar mass NaNO3

mass of NaNO3 = moles * molar mass =

= 6.75 moles * 85.00 g/mole

= 573.75 g = 574 g

Pie · Answer 2 · 2022-05-18T16:31:22+03:00

Pie3 years ago

5 0

Answer:

574 g

Explanation: