The greatest counting number that divides 17, 25 and 41 and leaves the same remainder in each case is 8
Answer:
The first 5 terms are;
-2, 2, 13,38 and 91
Step-by-step explanation:
Here, we want to write the first 5 terms of the sequence.
We already have the first term as 1
Now, we need the 2nd term
Putting two in place of n, we have ;
2f(1) + 3n
= 2(-2) + 3(2) = -4 + 6 = 2
For the 3rd term, put 3 in place of n
2f(2) + 3(3)
sine f(2) = 2, we have
2(2) + 9 = 4+ 9 = 13
For the fourth term, put 4 in place of n, we have
2f(3) + 3(4)
since f(3) = 13
we have; 2(13) + 12 = 26 + 12 = 38
For the 5th term, put 5 in place of n, we have
2f(4) + 3(5)
since f(4) = 38, we have
2(38) + 15 = 76 + 15 = 91
X ・y^5
x times y to the fifth
Answer:
- 11
Step-by-step explanation:
integer = x
Three times what integer, plus eight equals 3x+8
Three times what integer, plus eight equals negative 25. 3x+8= -25
3x+8= -25
3x = -25 - 8
3x = - 33
x = -33/3 = -11
Answer:
The Answer is 4.79
Step-by-step explanation:
All you have to do Divide 33.53 by 7 then you would get 4.79
I say divide because they want to know how much it one gallon of milk costs So that is why you have to divide
Hope I Helped! :3
