There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
When it's 5th to the power you do the number by itself how many times the power is so the correct way would be
10×10×10×10×10
Answer: the answer would be 7
Step-by-step explanation:
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Answer:
option A.. 10 days
Step-by-step explanation:
option is 10 days is the correct answer
in one day he eats = 1and1/5 cups = 6/5 cups
one cup last for = 5/6 day
12 cups last for days = 12× 5/6 = 2× 5 = 10 days
so correct answer is 10 days ... option A
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Answer:
4/3 or 1.3333333...
Step-by-step explanation:
2 x (3x + 1)-4 = 6.
6x+2-4=6.
6x+2=10
6x=8.
X= 1.3333333... OR 4/3
