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-BARSIC- [3]
1 year ago
11

Write a quadratic equation with a integer coefficients with roots x= 1/2 and x=-4

Mathematics
1 answer:
Misha Larkins [42]1 year ago
8 0

The quadratic equation with roots a and b is given by:

x^2-(a+b)x+ab=0

Here a=1/2 and b=-4.

So the equation is given by:

\begin{gathered} x^2-(\frac{1}{2}-4)x+(\frac{1}{2})(-4)=0 \\ x^2+\frac{7}{2}x-2=0 \\ 2x^2+7x-4=0 \end{gathered}

The quadratic equation is as shown above.

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In triangle ABC, a=7, b=3 and cos C = 1/2. The value of c is
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Answer:

Correct option: 2 -> sqrt(37)

Step-by-step explanation:

To solve this problem, we just need to use the law of cosines. This law is used to find the third side of a triangle, when we have the two other sides and the angle between them.

The equation of the law of cosines is:

c^2 = a^2 + b^2 - 2 * a * b * cos(C)

So, we have that:

c^2 = 7^2 + 3^2 - 2 * 7 * 3 * (1/2)

c^2 = 49 + 9 - 21

c^2 = 37

c = sqrt(37)

Correct option: 2

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3 years ago
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tensa zangetsu [6.8K]
8 is the correct answer
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