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3 years ago

Can someone help me with 30-32 please?

Mathematics

1 answer:

Harman [31]3 years ago

8 0

30 is A to the second power 31 is X to the first power 32 is just M

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Please help asap! Tysm! I will give brainliest and thanks. :)

dsp73

Answer:

(-2,4)

Step-by-step explanation:

There are multiple answers for this, basically anything with an x-value of: -4, -2, 0, 2, or 4

So, you could have (2,4) , (-4,3) , (0,17), (2, -5), etc.

This is because, to be a function, each x-value can only have one corresponding y-value. Thus, by giving the x-values (in this case, again, -4,-2,0,2, or 4) another y-value, the relation will not be a function.

Easy answer: An x-value can only have one y-value

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3 years ago

One leg of a right triangle has length 7. The lengths of the other two sides are whole numbers. The length of the other leg is _

Gekata [30.6K]

It should be 7, 24 and 25

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3 years ago

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago

If the number of professors in a college is P and the number of students is S, and there are 19 times as many students as profes

morpeh [17]

Answer:

$S =19P\\S-19P = 0$

Step-by-step explanation:

We are given the following in the question:

Let P be the number of professor and S be the student in a college.

According to the question:

There are 19 times as many students as professors.

We have to write an equation to show the given relationship between professors and students.

$S =19P\\S-19P = 0$

The above situation is the situation that represents the given relationship.

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3 years ago

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MAXImum [283]

The first one is 24 the second is 96

7 0

3 years ago