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eduard
3 years ago
5

X/(x ^ 2 + 3x + 2) + 3/(x + 1)

Mathematics
1 answer:
masya89 [10]3 years ago
4 0
Answer: 2(2x+3)/(x+1)(x+2)
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How many quarts, rounded to the nearest tenth, are in 50 liters
Lyrx [107]

Answer:

about 55 quarts

Step-by-step explanation:

1.1 * 50

6 0
2 years ago
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∛27x1000????????????????????????????????????
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3000

Step-by-step explanation:

.......... Follow the step above

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What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
3 years ago
Of the 100 entries in a costume contest, 39 entrants were dressed as heroes and 45 entrants were wearing a mask. If 21 entrants
ehidna [41]

Correct question with correct options has been attached

Answer:

37

Step-by-step explanation:

Let C represent those dressed as heroes and let B represent those wearing mask

Thus;

n(C) = 39

n(D) = 45

We are told that 21 entrants were dressed as heroes wearing a mask.

Thus; n(C n D) = 21

We are also told that there were a total of 100 entries.

Thus, n(T) = 100

Now, number of entrants neither dressed as heroes nor wearing a mask is given by;

n(T) - n(C u D)

n(C u D) = n(C) + n(D) - n(C n D)

n(C u D) = 39 + 45 - 21

n(C u D) = 63

Thus;number of entrants neither dressed as heroes nor wearing a mask is: 100 - 63 = 37

3 0
3 years ago
I need help I hope it uploaded the pic
jenyasd209 [6]
A number that's bigger than 4.3 is the answer :)
8 0
3 years ago
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