I’m pretty sure k=59 degrees since the area of a triangle is 180 so you just subtract the angles you already have to find the other one
Answer:
58°
Step-by-step explanation:
If m AM=125°, then m∠AOM=125°.
If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).
Thus,
m∠FOA=360°-150°-125°=85°.
If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).
Hence,
m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.
Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus
m∠AME=1/2m∠EOA=58°.
You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.
Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.
For sine function, can be written as:
- A = amplitude
- b = period = 2π/b
- c = horizontal shift
- d = vertical shift
I am not able to provide an attachment for an easy view but I will try my best!
We know that amplitude or A is a distance from baseline/midline to the max-min point.
Let's see the example of equation:
Refer to the equation above:
- Amplitude = 2
- b = 1 and therefore, period = 2π/1 = 2π
- c = 0
- d = 0
Thus, the baseline or midline is y = 0 or x-axis.
You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.
So to conclude or say this:
If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.
Answer:
true.
Step-by-step explanation:
the line only passes through the y-intercept once.
Answer:
the answer is x=6 or x=-16