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Alisiya [41]
3 years ago
11

Which expression is equvilanent to 10q + 5 A.5q+5q+5 B.10q+5+5 C.5q+10 D.5q+5

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0
I think is alternative a
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pickupchik [31]
Substituting the value of X in each of the equations.The best answer would be the equation satisfying both of the sides.
Therefore,
Substituting the values in the second equation gives the best answer.
8(1.2)^2 + 34 = 45.52 centimeters
7 0
3 years ago
Read 2 more answers
40% of the memberships sold by Gym A were gold memberships.
Aneli [31]

Answer:

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

Step-by-step explanation:

Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.  

Which statement must be true?

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.

c) Gym A sold more gold membership than Gym A did.

d) If Gym B sold 50 membership, 25 would be gold memberships.

Given: Gym A have sold 40% gold membership of total membership.

Gym B have sold 25% gold membership of total membership.

Lets take option A first to find if it is true statement.

As per option A, There are total number of membership is 80.

∵ Gym A has sold 40% gold membership.

∴ Gym A gold membership= 40\% \times 80

⇒ Gym A gold membership= \frac{40}{100} \times 80= 32 member.

∴ Gym A gold membership= 32.

Now, Gym B

∵ Gym B has sold 25% gold membership.

∴ Gym B gold membership= 25\% \times 80

⇒ Gym B gold membership= \frac{25}{100} \times 80=20 member.

∴ Gym B gold membership= 20.

Next finding difference gold membership for Gym A and Gym B

32-20= 12 \ membership

Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.

8 0
3 years ago
Match each equation with a value of x that satisfies it
Alexus [3.1K]

Answer:

(x-2)^1/4=2 ---> 18

√x^2+7=4. ---> -3

^3√1-x=-1. ---> 2

Step-by-step explanation:

just did it on plato

5 0
3 years ago
Can someone please help mee
Andrew [12]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:Domain = [-9, -1]

\qquad \tt \rightarrow \:Range = [-1 , 3]

____________________________________

\large \tt Solution  \: :

Domain = All possible values of x for which f(x) is defined

[ generally the extension of function in x - direction ]

Range = All possible values of f(x)

[ generally the extension of function in y - direction ]

\large\textsf{For the given graph : }

\qquad \tt \rightarrow \: domain = [ - 9, -1]

\qquad \tt \rightarrow \: range= [ -1,3]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

3 0
2 years ago
Which equation can be solved by using this system of equations? startlayout enlarged left-brace 1st row y = 3 x superscript 5 ba
Mariulka [41]

An equation which can be used to solve the given system of equations is 3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11.

<u>Given the following data:</u>

y = 3x⁵ - 5x³ + 2x² - 10x + 4

y = 4x⁴ + 6x³ - 11

<h3>What is a system of equations?</h3>

A system of equations can be defined an algebraic equation that only has two (2) variables and can be solved simultaneoulsy.

Equating the given equations, we have:

y = y

3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11

3x⁵ - 5x³ + 2x² - 10x + 4 - (4x⁴ + 6x³ - 11) = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 4x⁴ - 11x³ + 2x² - 10x + 15 = 0

Read more on equations here: brainly.com/question/13170908

3 0
2 years ago
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