Answer: Option A
![y=\left \{ {{x^2 +2;\ \ x](https://tex.z-dn.net/?f=y%3D%5Cleft%20%5C%7B%20%7B%7Bx%5E2%20%2B2%3B%5C%20%5C%20x%3C1%20%5Catop%20%7B-x%2B2%3B%5C%20%5C%20x%5Cgeq1%7D%7D%20%5Cright.)
Step-by-step explanation:
In the graph we have a piecewise function composed of a parabola and a line.
The parabola has the vertex in the point (0, 2) and cuts the y-axis in y = 2.
The equation of this parabola is
Then we have an equation line![y = -x + 2 ](https://tex.z-dn.net/?f=%20y%20%3D%20-x%20%2B%202%0A)
Note that the interval in which the parabola is defined is from -∞ to x = 1. Note that the parabola does not include the point x = 1 because it is marked with an empty circle " о ."
(this is
)
Then the equation of the line goes from x = 1 to ∞ . In this case, the line includes x = 1 because the point at the end of the line is represented by a full circle
.
(this is
)
Then the function is:
![y=\left \{ {{x^2 +2;\ \ x](https://tex.z-dn.net/?f=y%3D%5Cleft%20%5C%7B%20%7B%7Bx%5E2%20%2B2%3B%5C%20%5C%20x%3C1%20%5Catop%20%7B-x%2B2%3B%5C%20%5C%20x%5Cgeq1%7D%7D%20%5Cright.)