Answer:
A weak fuel to air mixture along with normal airflow through a turbine engine may result in <u>a lean die out</u>.
Explanation:
Lean die out is a type of problem that may occur in the turbine. This may result in the weak fuel to air mixture. In case if the mixture of fuel and air is getting low due to some reasons like leakage of gas or low speed of engine may result in dangerous conditions such as fire or blast in the turbine. This is called lean die out. In the result of this problem, the turbine can be burn with the blast and may leads to causalities.
By looking up your research on websites that have (.org) or wikipedia for answers u might have to find information
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
