Answer:
Third week = 23.35 miles
Step-by-step explanation:
First week total miles = 15 miles
he would like to run 30% more miles each week than the week before
Second week = 15 miles + (30% of 15 miles)
= 15 + (30% * 15)
= 15 + (0.3 * 15)
= 15 + 4.5
= 19.5 miles
Second week = 19.5 miles
Third week = 19.5 miles + (30% of 19.5 miles)
= 19.5 + (30% * 19.5)
= 19.5 + (0.3 * 19.5)
= 19.5 + (5.85)
= 23.35 miles
Third week = 23.35 miles
<> because it means greatest and least only
It’s D because if he withdrawals u would minus
15. 3x - 2y = -2
3x - 3x - 2y = -3x - 2
-2y = -3x - 2
-2 -2
y = 1.5x + 1
y - y₁ = m(x - x₁)
y - 3 = ⁻²/₃(x - (-2))
y - 3 = ⁻²/₃(x + 2)
y - 3 = ²/₃(x) - ²/₃(2)
y - 3 = ⁻²/₃x - 1¹/₃
+ 3 + 3
y = ⁻²/₃x + 1²/₃
16. 230 = 0.2s + 150
- 150 - 150
80 = 0.2s
0.2 0.2
400 = s
17. y = 2x + 2
My solution to the problem is as follows:
<span>day 1: 1
day 2: 0.6667
day 3: 0.5111
day 4: 0.4385 <-------
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Therefore, <span>the probability that the animal is in the woods on fourth observation would be 0.4385.
I hope my answer has come to your help. God bless and have a nice day ahead!
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