If the animal is in the woods on one observation, then it is four times as likely to be in the woods as the meadows on the next
1 answer:
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Answer:
64.5%
Step-by-step explanation:
Initial amount N° = ?
Remaining amount after decay = N = ?
k = decay constant = 0.00012
t = time = 3650 year
fraction remaining will be N/N°
From the decay equation, N = N°
N/N° =
N/N° =
N/N° =
N/N° = 0.645 = 64.5%