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Leni [432]
2 years ago
9

Some current research efforts are investigating whether or not ________, a group of prokaryotes with the ability to produce oxyg

en as a by-product of photosynthesis, can be used as a source of renewable energy by converting sunlight into electricity.
Biology
1 answer:
WITCHER [35]2 years ago
6 0
<h2>Cyanobacteria </h2>

Explanation:

Simple cyanobacteria (single-celled organisms that can produce oxygen through photosynthesis) played a key role in providing Earth’s atmosphere and oceans with oxygen

Cyanobacteria or the blue green algae are the only bacteria that contain chlorophyll A, a chemical required for oxygenic photosynthesis, the process which uses carbon dioxide, water and sunlight to produce oxygen and glucose (sugars) for energy

In this process chlorophyll A helps in capturing the energy from sunlight

In addition to chlorophyll A, blue-green algae also contain the pigments phycoerythrin and phycocyanin, which give the bacteria their bluish tint    

All the above characteristics of cyanobacteria can be used as a source of renewable energy by converting sunlight into electricity

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Which of the following is the best description of the theory of evolution
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It is a theory supported by overwhelming scientific evidence.

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A scientist wishes to determine the effect of a digestive enzyme on starch digestion (starch is broken down into glucose). The e
Sladkaya [172]

Answer:

An identical setup but replacing the enzyme with an equal volume of water

Explanation:

When carrying out any experiment, it is important to set out a control in order to increase the reliability of the data and results.

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4 0
2 years ago
First person to answer gets brainlist.
Vikki [24]

This statement is true.

3 0
3 years ago
Read 2 more answers
For this question, we will utilize a population of Martians that is in Hardy Weinberg Equilibrium. The dominant Martian phenotyp
Brrunno [24]

Answer:

d.0.48

Explanation:

When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:

freq (AA) = p²

freq (Aa) = 2pq

freq (aa) = q²

<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.

In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.

Therefore:

q²=16/100

q² = 0.16

q=√0.16

q = 0.4

And p+q=1, so:

p = 1 - q

p = 1-0.4

p = 0.6

The frequency of heterozygotes is:

freq (Aa) = 2pq = 2 × 0.4 × 0.6

freq (Aa) = 0.48

5 0
3 years ago
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