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3 years ago

Name a cause and effect for each of the following:

1 answer:

8 0

Deforestation, Desertification and Urbanization are very closely related phenomenon whose cause and effects are briefly discussed below.

<h3><u>Explanation:</u></h3>

Deforestation is caused due to cutting of trees for economic purposes and other poachers.

Deforestation effects the natural habitat of the animals of forests leading to endangering of different plants and animals. It also reduces diversity of environment, causes global warming, change in climate, rainfall patterns etc.

Desertification is caused due to deforestation, due to natural calamities like forest fires, overgrazing and even due to over population.

Desertification causes a huge loss to environment. Erosion of soil, deepening of ground water levels, loss of rainfall, draught are common. Rise in temperature and change of climates are also seen.

Urbanisation is caused by main two reasons - over population and rural to urban migration of people.

Urbanization has several good effects like growth of technologies etc. But it also increases disease rates due to increase in pollution. Several mental stress and depression are also seen to affect urban people more than rural ones.

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3 years ago

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nexus9112 [7]

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3 years ago

Difference between qualitative and quantitative data in chemistry

const2013 [10]

Quantitative data is numerical.
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7 0

3 years ago

Carbon dioxide (1.100g) was introduced into a 1L flask which contained some pure oxygen gas. The flask was warmed to 373K and th

Semenov [28]

Answer : The mass of oxygen present in the flask is 0.03597 grams.

Explanation :

First we have to determine the moles of $CO_2$ gas.

$\text{ Moles of }CO_2=\frac{\text{ Mass of }CO_2}{\text{ Molar mass of }CO_2}=\frac{1.100g}{44g/mole}=0.025moles$

Now we have to calculate the moles of the oxygen gas.

Using ideal gas equation:

$PV=nRT$

As, the moles is an additive property. So,

$PV=(n_{O_2}+n_{CO_2})RT$

where,

P = pressure of gas = 608 mmHg = 0.8 atm

(conversion used : 1 atm = 760 mmHg)

V = volume of gas = 1 L

T = temperature of gas = 373 K

$n_{O_2}$ = number of moles of oxygen gas = ?

$n_{CO_2}$ = number of moles of carbon dioxide gas = 0.025 mole

R = gas constant = $0.0821L.atmK^{-1}mol^{-1}$

Now put all the given values in the ideal gas equation, we get:

$(0.8atm)\times (1L)=(n_{O_2}+0.025)mole\times (0.0821L.atmK^{-1}mol^{-1})\times (373K)$

$n_{O_2}=0.001124mole$

Now we have to calculate the mass of oxygen gas.

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=0.001124mole\times 32g/mole=0.03597g$

Therefore, the mass of oxygen present in the flask is 0.03597 grams.

7 0

4 years ago

Calculate the molecular (formula) mass of each compound: (a) iron(ll) acetate tetrahydrate; (b) sulfur tetrachloride; (c) potass

Nutka1998 [239]

Answer:

a) Iron(ll) acetate tetrahydrate: 245,68 g/mol

b) Sulfur tetrachloride: 173,87 g/mol

c) Potassium ermanganate 158,034 g/mol

Explanation:

To solve this kind of exercises you must look for the number of atoms in each molecule first, then look on the periodic table the atom weight and the multiply the atom weight times the quantity of each atom. For instance:

The molecule of Iron(II) acetate itetrahydrate is (CH3COO)2Fe•4H2O, it means that you have:

2 atoms of carbon times the atomic weight of C (12.00g/mol)= 24g

14 atoms of Hidrogen times the atomic weight of H (1,00g/mol)= 14g

6 atoms of Oxigen times the atomic weight of O (16,0g/mol)= 96

2 atoms of Iron times the atomic weight of Fe (55,84g/mol)= 111,68g

At last, you only have to add the results: 24+14+96+11,68= 245,68g/mol. This example was for the first molecule.

See you,

5 0

3 years ago