The plane PRS passes through the points P, R and S. So it contains the line RS. Also the plane QRS passes through the points Q, R and S. So it contains the line RS as well. Since both the planes contain the line RS, the line RS must be the intersection of plane PRS and QRS
D is the answer
hope i helped
If you would like to write y - x - 1 = 0 in the general form, you can do this using the following steps:
The general form of the equation is: ax + by + c = 0.
y - x - 1 = 0
-x - y - 1 = 0
The correct result would be <span>-x - y - 1 = 0</span>.
Answer:
g(x) = 3(x-9)(x-5)
Zeros: x = 9 and x = 5.
Step-by-step explanation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question:
So
So
g(x) = 3(x-9)(x-5)
Zeros: x = 9 and x = 5.
