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2 years ago

HELP! I will give brainliest!! This is overdue!!!

Mathematics

1 answer:

Vanyuwa [196]2 years ago

6 0

Answer:

The shorter side 6th ft and the longer sides are 11ft

Step-by-step explanation:

The options are not given, but we could solve and arrive at an answer

say the shorter side is x

and the longer side is x+5

we know that the area of a rectangle is given as

x*(x+5)=66

open the bracket

x^2+5x=66

x^2+5x-66=0

Find two factors of -66 whose sum equals the coefficient of the middle term, which is 5 .

the factors are 11 and -6

splitting the middle term using the two factors 11 and -6

x2 +11x - 6x - 66=0

x(x+11)-6(x+11)=0

(x-6)=0

x=6

(x+11)=0

x=-11

The shorter side is 6 ft and the longer side is 11 ft

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Jamel is asked to create triangles using three of four given sticks. The sticks measure 3 in., 6 in., 7 in., and 8 in. He create

Dmitriy789 [7]

Let c = hypotenuse and a = leg 1 and b = leg 2. If c² > a² + b², then it is obtuse. If it is less, then it is acute. I hope it helps.

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3 years ago

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A line of best fit predicts that when x equals 28 y will equal 27.255 but y actually equals 26 what is the residual in this case

Kobotan [32]

Answer:

The answer is -1.255 for residual value.

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

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Residual values = -1.255

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3 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ factoring 96

since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

using exponent rule - $(a^{b}) ^{c} = a^{bc}$

$\sqrt{2^{5} } = 2^{5/2}$

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

doing some simple simplification and $4=2^{2}$ and 6=2*3

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

collecting the roots on one side and applying exponent rule

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$

7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

combining all powers of 2

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

Simplifying

9. $2^{9} *3^{2}\sqrt{3}$

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3 0

3 years ago

Read 2 more answers

Area of a Triangle

jek_recluse [69]

Answer:

3.51 (round to the nearest hundreds)

Step-by-step explanation:

PART A

slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5

equation of the line passing through B and perpendicular to AC:

y-3 = 1/5(x-3)

y-3 = 1/5x -3/5

y = 1/5 x - 3/5 + 3

y = 1/5 x + (-3+15)/5

y = 1/5 x + 12/5

PART B

line that passes through the points A and C

y-1 = -5(x-2)

y = -5x+10 + 1

y = -5x + 11

Interception of the lines

y = 1/5x + 12/5

y = -5x + 11

-5x + 11 = 1/5x + 12/5

-25x +55 = x + 12

26x = 43

x = 43/26

y = -5(43/26) + 11

y= -215/26 + 11

y = (-215+286)/26 = 71/26

D (1.65, 2.73)

PART C

AC = $\sqrt{(1-2)^2 + (6-1)^2} = \sqrt{1 + 25} = \sqrt{26}$ = 5,09902

BD = $\sqrt{(3-1.65)^2 + (3-2.73)^2}$ = 1,376735

PART D

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3 years ago

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 50.7 d

Svet_ta [14]

Answer: The mean of the frequency distribution is 51.7°.

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Step-by-step explanation:

The given table :

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Class interval f x fx

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45-49 7 47.5 95

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60-64 1 62.5 25

$\text{Now, Mean}=\dfrac{\sum fx}{\sum f}\\\\=\dfrac{85+332.5+472.5+287.5+62.5}{24}\\\\=\dfrac{1240}{24}=51.6666666667\approx51.7$

The computed mean 51.7° is greater than the actual mean 50.7° .

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3 years ago