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2 years ago

3. What is the solution to the equation 3x = 15? Express the

Mathematics

1 answer:

ivanzaharov [21]2 years ago

4 0

Answer:

x=2.4650

Step-by-step explanation:

I assume that you mean $3^x=15$

so let s use the ln() function

$ln(3^x)= xln(3)=ln(15)$

so x = ln(15)/ln(3)

x = 2.4650

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2 years ago

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3.2 geometry worksheet

alekssr [168]

Answer/Step-by-step explanation:

5. 21x + 4 = 22x - 2 (corresponding angles)

Collect like terms

21x - 22x = -4 - 2

-x = -6

divide both sides by -1

x = 6

6. (x + 72) + (x + 132) = 180 (linear pair)

x + 72 + x + 132 = 180

Add like terms

2x + 204 = 180

2x = 180 - 204

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x = -12

7. 90 = 22x + 2 (vertical angles)

90 - 2 = 22x

88 = 22x

Divide both sides by 22

4 = x

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8. 12x + 10 = 13x + 3 (vertical angles)

Collect like terms

12x - 13x = -10 + 3

-x = -7

Divide both sides by -1

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9. 17x = 16x + 5 (alternate exterior angles)

17x - 16x = 5

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✔️17x

Plug in the value of x

17(5) = 85°

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3 0

3 years ago

2. Saul invested an average of $425 per month since age 30 in various securities for his

BabaBlast [244]

Answer:

$507.30

Step-by-step explanation:

-Given the monthly deposits are $425 and the interest rate is 3.5% for 30 years.

-The amount of the investment after 30 years is calculated as;

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{30\times 12}\\\\=1212.65$

-Assuming Saul started saving at age 20, his investment term will be 40 yrs.

-His investment amount is thus:

$A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{40\times 12}\\\\=1719.95$

#We subtract to find how much more he would have if he started saving at 20;

$=A_{20}-A_{30}\\\\=1719.95-1212.65\\\\=507.30$

Hence, Saul would have $507.30 more had he started saving 10 years earlier.

5 0

3 years ago