Answer:
In step 2, she didn’t use an x and y from the same coordinate pair
Step-by-step explanation:
see the attached figure to better understand the problem
we have the points (5, 1) and (3, 5)
step 1
Find the slope
The formula to calculate the slope between two points is equal to
substitute
step 2
The equation of the line in point slope form is
take the point (3,5)
substitute
step 3
therefore
In step 2, she didn’t use an x and y from the same coordinate pair
R = 4 x + 8y [ Given ]
when ,
x = 4 and R = 32
★ Substituting the values
=> 32 = 4 × 4 + 8y
=> 32 = 16 + 8y
=> 8y = 32 - 16
=> 8y = 16
=> y = 8/16
=> y = 2
I believe the answer is sometimes
We are given the graph of sine function.
First, we get the amplitude
A = [6 - (-2)] / 2
A = 4
Next, we determine the period and b
T = 4 - 0 = 4
b = 2π / T
b = π/2
The original sine function was
y = 4 sin πx/2
After the transformation, the equation now is
y = 4 sin [π(x+2)/2] + 2
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
