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3 years ago

2/3 = 20/30 what numbers are the means of the proportion shown below? PLEASE NEED HELP *

Mathematics

2 answers:

pashok25 [27]3 years ago

6 0

Answer:

The answer of your doing apex is 3 and 20 have a great day!

Step-by-step explanation:

netineya [11]3 years ago

5 0

Please elaborate the question

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IM just a little bit slow

viva [34]

Answer:

71°

Step-by-step explanation:

31-3x+19x-5=90

16x=90-26

16x=64

x=4

m<R=19x-5 = 19(4)-5 = 76-5 = 71

5 0

3 years ago

Read 2 more answers

Chris and Becky are comparing mortgages. The mortgage is for $183,500. If they choose 30 years at 5%, their monthly payment will

Anestetic [448]

Answer:

Total payback for Loan type 1 = $354,625.20

Total payback for Loan type 2 = $278,618.40

Explanation

Total payback of a loan consists of the summation of the amount of mortgage to be paid and total interest to be paid after the given number of years.

Total payback of a loan can also be calculated by multiplying your monthly payment of the loan by the total number of months given for payment.

a. For Loan type 1

In the question we have been given or monthly payment = $985.07

The formula for Total payback for Loan type 1 = Monthly payment × number of months

Numbers of years for payment of loan = 30 years

1 years = 12 months

Hence,

Number of months = 30 years × 12 months

Number of months = 360 months

Total payback of loan = $985.07 × 360 months

= $354,625.20

b. For Loan type 2

In the question we have been given or monthly payment = $1160.91

The formula for Total payback for Loan type 1 = Monthly payment × number of months

Numbers of years for payment of loan = 30 years

1 years = 12 months

Hence,

Number of months = 20 years × 12 months

Number of months = 240 months

Total payback of loan = $1160.91 × 240 months

= $278,618.4

Step-by-step explanation:

4 0

3 years ago

The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds

boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation $h=-16t^2+24t+16$ , where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation $h=-16t^2+24t+16$ , we get,

$0=-16t^2+24t+16$

Switch sides, we have,

$-16 t^{2}+24 t+16=0$

Let us solve the equation using the quadratic formula.

Thus, we have,

$t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}$

Simplifying, we get,

$t=\frac{-24 \pm \sqrt{576+1024}}{-32}$

$t=\frac{-24 \pm \sqrt{1600}}{-32}$

$t=\frac{-24 \pm 40}{-32}$

Hence, the two values of t are

$t=\frac{-24 + 40}{-32}$ and $t=\frac{-24 -40}{-32}$

Simplifying the values, we get,

$t=\frac{16}{-32}$ and $t=\frac{-64}{-32}$

Dividing, we get,

$t=-\frac{1}{2}$ and $t=2$

Since, t cannot negative values, we have,

$t=2$

Thus, the rock will hit the ground at 2 seconds.

8 0

3 years ago

can some one also please help my one that i should do after i finds the area of the square aka how to find the area of the trian

Andre45 [30]

Answer:

6 square units

Step-by-step explanation:

Given shape is of a trapezoid:

$area \: of \: trapezoid \\ = \frac{1}{2} \times (4 + 2) \times 2 \\ \\ = 6 \: {units}^{2}$

Area of shape = area of square + area of triangle

$= 2^2 + \frac{1}{2} \times 2\times 2\\= 4 + 2\\= 6\: units^2 \\$

4 0

4 years ago

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

6 0

4 years ago