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sveta [45]
3 years ago
5

can some one also please help my one that i should do after i finds the area of the square aka how to find the area of the trian

gle.

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

6 square units

Step-by-step explanation:

Given shape is of a trapezoid:

area \: of \: trapezoid  \\ =  \frac{1}{2}  \times (4 + 2) \times 2 \\  \\  = 6 \:  {units}^{2}

Area of shape = area of square + area of triangle

= 2^2 + \frac{1}{2} \times 2\times 2\\= 4 + 2\\= 6\: units^2 \\

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Suzy is starting a babysitting buisness. She spent $ 36 to make signs to advertise. She charges and intial fee of $ 6 and then $
timofeeve [1]

Answer:

3h - 30 > 0

h > 10

Step-by-step explanation:

To make a profit, subtract $36 in cost from the income coming in.

She charges $6 and then $3 per hour or 3h. Her income coming in is 6 + 3h.

Subtract 36 from it to find the profit.

3h + 6 - 36

3h - 30

To make a profit, she needs to make more than $0 or > 0.

3h - 30 > 0

Solve using inverse operations.

3h - 30 > 0

3h > 30

h > 10

3 0
3 years ago
Subtract 6x 2 −7x−2 from 6x^{2}-2x+6
ki77a [65]

Answer:

5x+8

Step-by-step explanation:

The from is the key word

That means the second term is first

6x^2 -2x +6 - (6x^2 -7x -2)

Distribute the minus sign

6x^2 -2x +6 - 6x^2 +7x +2

Combine like terms

5x+8

3 0
2 years ago
What’s the solution set for x? Can someone please answer and explain how they got they’re answer for 40 points.
xz_007 [3.2K]

Answer:

i think the answer is 2.I had a problem like this and i think u have to find out what both of them equal

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3 years ago
Compare the two groups of data. Which statement is true?
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D
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8 0
2 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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