All categories

3 years ago

What is the common difference of the arithmetic sequence 5, 8, 11, 14?

Mathematics

1 answer:

AnnZ [28]3 years ago

3 0

Answer:

The common difference is 3

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant called the common difference

we have

$5,8,11,14$

$a1=5$

$a2=8$

$a3=11$

$a4=14$

$a2-a1=8-5=3$

$a3-a2=11-8=3$

$a4-a3=14-11=3$

therefore

The common difference is 3

You might be interested in

1. Write the following radicals in simplest form a) -3√288 b) 5√320

jeka57 [31]

A) -3√288=-3√(144*2)=-3√144√2=-3*12√2=-36√2

b) 5√320=5√(64*5)=5√64√5=5*8√5=40√5

8 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago

Help plz with this problems

prohojiy [21]

To find the perpendicular slope, we simply flip the fraction (aka reciprocal) and flip the sign (go from positive to negative, or vice versa)

So for problem 1a) we flip the fraction to go from 4/3 to 3/4. Then we flip the sign to go from +3/4 to -3/4. The final answer to problem 1a) is -3/4

The answer to problem 1b) is 7/3 following the same basic steps: -3/7 ---> -7/3 ---> 7/3

The answer to problem 1c) is -1/4. You can think of 4 as 4/1 which flips to 1/4 and it becomes -1/4

I'll let you try out the rest 1d and 1e. Tell me what you get so I can check your answers.

3 0

3 years ago

How you solve -9+[b-8]=-5

sertanlavr [38]

your answer is B= 12 your welcome :)

8 0

3 years ago

I can do your homework for you

marshall27 [118]

Answer:

thanks for the free points

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers