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SOVA2 [1]
3 years ago
6

How do you solve this In this case 1422 = 5534/(1+r)^4

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0
It is okay to take the inverse of both side given that you remember to exclude the value that make the denominator  zero which is in this case r=-1

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4 0
2 years ago
What is b in terms of a and c?
aev [14]

Answer:

b=\sqrt{c^2-a^2}

Step-by-step explanation:

The given relation is

c=\sqrt{a^2+b^2}

To make b the subject, we square both sides of the equation to get;

c^2=(\sqrt{a^2+b^2})^2

c^2=a^2+b^2

Isolate b on one side of the equation;

c^2-a^2=b^2

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b^2=c^2-a^2

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6 0
3 years ago
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Answer:

Step-by-step explanation:

a.

£100

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b.

£80

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5/8×£80

=£50

C.

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2:3:5

2+3+5=10

2/10×£250

=£50

3/10×£250

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5/10×£250

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6 0
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3 years ago
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