Question

X^2+20x+11=-8 pls help me I need it now pls help

Answer 1

Answer:

x = -19   or   x = -1

Step-by-step explanation:

$x^2 + 20x + 11 = -8$

We need the quadratic equation in the form

$ax^2 + bx + c = 0$,

so we add 8 to both sides.

$x^2 + 20x + 19 = 0$

Now we have an equation of the form x^2 + ax + b = 0.

We need to factor the quadratic equation. To factor it, we need two numbers, p and q, whose product is b and whose sum is a. Then the factoring is (x + p)(x + q).

In our case, b = 19 and a = 20. We need two numbers that multiply to 19 and add to 20. The numbers are 19 and 1. Our p and q are 19 and 1.

(x + 19)(x + 1) = 0

Since a product of two factors equals zero, either one factor equals zero, or the other factor equals zero. We set each factor equal to zero and solve both equations for x.

x + 19 = 0   or   x + 1 = 0

x = -19   or   x = -1