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mojhsa [17]
3 years ago
13

You are packing presents. You cut a ribbon every 40 inches, and you have 7 pieces. There are 30 inches of ribbon left. How long

was the ribbon at first?
Mathematics
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

The ribbon was 310 inches long at first.

Step-by-step explanation:

First, we will determine the length of ribbon that was cut.

From the question,

You cut a ribbon every 40 inches, that is, the length of each ribbon is 40 inches

Since, we have 7 pieces of ribbon, then total length of the ribbon that was cut will be

40 inches × 7

= 280 inches

This the total length of ribbon that was cut from the initial length of ribbon.

Now, after cutting 7 pieces of ribbon, there are 30 inches of ribbon left,

To determine how long the ribbon was at first,

we will sum the total length of ribbon that was cut from the initial length to the remaining length of ribbon after cutting, that is

280 inches + 30 inches

= 310 inches

This is the initial length of the ribbon.

Hence, the ribbon was 310 inches long at first.

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4 years ago
What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?​
Dominik [7]
The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
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Slope of the line:

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3 years ago
Read 2 more answers
Write the ratio in the simplest form 3 cups of sugar to 27 cups of milk
Verizon [17]

Answer: 3:27

you would divide both by 3

3/3 =1

27/3= 9

so your ratio in simplest form is 1 cup of sugar: 9 cups of milk

4 0
4 years ago
Give the algebraic expression by using variables and constant and arithmetic operations: i. Sum of the squares of x and y. ii.Pr
Olenka [21]

Answer:

a) x^2 + y^2

b) 9-xy

Step-by-step explanation:

Here, we want to write the algebraic statements as expressions;

a) The sum of the squares of x and y

The square of x is x^2

The square of y is y^2

The sum of the squares is x^2 + y^2

ii) Product of x and y subtracted from 9

The product of x and y is x * y = xy

Subtracting these from 9, we have;

9-xy

5 0
3 years ago
A two-digit number becomes 5/6 of the reversed number obtained when the digits are interchanged. The difference between the digi
stealth61 [152]
<h3>Answer:   54</h3>

==============================================

Work Shown:

T = tens digit

U = units digit (aka ones digit)

A number like 27 is really 20+7 = 2*10 + 7*1 = 10*2 + 1*7. We have 2 in the tens digit and 7 in the units digit. So 27 can be written in the form 10T + U where T = 2 and U = 7. Reversing the digits gives 72, so T = 7 and U = 2 now. Clearly the difference between the digits 7 and 2 is not 1, so 27 or 72 is not the answer (as it's just an example).

-----------------------

Let T be larger than U. This doesn't work if T = U.

Because T is larger, saying "The difference between the digits is 1" means T - U = 1. We can isolate T to get T = U+1. We'll use this later.

-----------------------

If T > U, then the original number 10T+U reverses to the new number 10U+T and it becomes smaller. We are told that it becomes 5/6 of what it used to be.

So,

new number = (5/6)*(old number)

10U + T = (5/6)(10T + U)

6(10U + T) = 5(10T + U)

60U + 6T = 50T + 5U

60U + 6(U+1) = 50(U+1) + 5U ... plug in T = U+1

60U + 6U + 6 = 50U + 50 + 5U

66U + 6 = 55U + 50

66U - 55U = 50-6

11U = 44

U = 44/11

U = 4 is the units digit of the original number

T = U+1

T = 4+1

T = 5 is the tens digit of the original number

The original number is therefore 10T + U = 10*5+4 = 54.

We see the difference in their digits is T-U = 5-4 = 1

The reverse of 54 is 45. The number 45 is 5/6 of 54

45 = (5/6)*54

7 0
3 years ago
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