4 years ago

Example: Find the smallest positive integer n so that 8!.n is aperfect square.

Mathematics

1 answer:

Goryan [66]4 years ago

5 0

Answer:

vkdjdduruyeyetjfdywreytdjgkjfkjgkhkhv;

Step-by-step explanation:

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Kaitlyn solved the equation for x using the following calculations. Negative 5.4 + x = 12.2. Minus 5.4. x = 6.8. What error, if

omeli [17]

Step-by-step explanation:

The equation that Kaitlyn solved is as follows :

-5.4+x=12.2

The steps to solve it as follows :

Step 1. Add 5.4 to both sides,

-5.4+x+5.4=12.2+5.4

Step 2. 5.4 will cancel out as both have opposite signs

x=17.6

But Kaitlyn solved it as :

5.4.x=6.8

She has multiplied -5.4 and x which is wrong. The correct answer is 17.6.

3 0

3 years ago

In which graph is y a linear function of x will mark brainiest

Nookie1986 [14]

Answer:

I think it is d

Step-by-step explanation:

hope this helps

6 0

3 years ago

The area of a circle, in terms of π, is 80π m2. Find the value of the radius. Give your answer as a simplified surd.

jolli1 [7]

Answer:

$r=4\sqrt{5}\:\: \sf m$

Step-by-step explanation:

$\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

Given:

Area = 80π m²

Substitute the given value into the formula and solve for r:

$\implies 80 \pi = \pi r^2$

$\implies \dfrac{80 \pi}{\pi} = \dfrac{\pi r^2}{\pi}$

$\implies 80=r^2$

$\implies \sqrt{r^2}=\sqrt{80}$

$\implies r=\sqrt{80}$

$\implies r=\sqrt{16 \cdot 5}$

$\implies r=\sqrt{16}\sqrt{5}$

$\implies r=\sqrt{4^2}\sqrt{5}$

$\implies r=4\sqrt{5}$

4 0

2 years ago

Read 2 more answers

Please help me please.

ValentinkaMS [17]

I think it's either 8 (16/2=8) OR 32 (16x2=32)

7 0

3 years ago

I’m doing a test and I need help ASAP

chubhunter [2.5K]

if the area is 16cm squared the diameter would be 4.51cm

The radius is half the diameter which would be 2.255cm

6 0

2 years ago

Example: Find the smallest positive integer n so that 8!.n is aperfect square.​

Example: Find the smallest positive integer n so that 8!.n is aperfect square.