Hey can someone please help me with this

I am thinking of six different odd numbers, the mean of the numbers is 16, the median is 15, the range is 26, the greatest numbe

Sedaia [141]

Answer:

Step-by-step explanation:

information from the range

If the range is 26 and the largest number is 31 then the smallest number is 31 - 26 = 5

Information from the median

The median must consist of 2 numbers because we have 6 integers for the data and median must consist of the middle 2. Since we are told that the median is 15 and we need 2 integers the other integer must be 15 as well..

So what do we know so far.

5 15 15 31

Information from the mean

There are six integers making up the series of numbers. The mean is 16. Therefore all 6 integers added together must be 6 * 16 = 96

What do we have so for?

5 + 15 + 15 + 31 = 66

What do the other two numbers sum to?

96 -66 = 30

Getting the answer.

The first number to try must be 13. It has to be below 15 (the median and odd. That's 13).

So now we have

5 13 15 15 ___ 31

But from the mean we need 30

30 - 13 = 17

And we have a winner because 17 is above 15.

Answer

5 13 15 15 17 31

4 0

2 years ago

How can I work it out to find the product of 7-3,7

romanna [79]

You should do 7-3=4 then do what’s u have to do with the 7

6 0

2 years ago

What radius of a circle is required to inscribe an equilateral triangle with an area of 35.074 in2 and an altitude of 7.794 in?

levacccp [35]

Answer:

(C) r=5.2 in

Step-by-step explanation:

firstly, we will draw diagram

we know that

centroid divides altitude into 2:1 form

so, we get

$r=\frac{2}{3}\times h$

now, we can plug

h=7.794

$r=\frac{2}{3}\times 7.794$

$r=5.196in$

so, option-C...............Answer

8 0

2 years ago

Which system of inequalities represents the graph?

vfiekz [6]

Yes the first one is the correct answer in this form of a graph

4 0

3 years ago

Step by step 7 ,9, and 11 please. EVEN IF U CANT DO ALL, u can help with 1 or 2. Ill mark brainly.

gregori [183]

Answer:

7) $4 \ log_3(x) - 4 \ log_3(y)$

9) $5log_4(7) - 5log_4(12)$

11) $5log_5 \ (x) - log_5 \ (y)$

Step-by-step explanation:

$log_3 (\frac{x}{y})^{4}$

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Use Logarithm of a Quotient which states

$log_b \frac{M}{N} = log_b M-log_bN$

And also use Logarithm of a Power which states

$log_b\ M^{n} = n\log_bM$

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So using these two properties,

7. $4 \ log_3(x) - 4 \ log_3(y)$

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For #9, use the same logarithm propertied

$log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)$

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#11 is also the same concept

$log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)$

It is not - 5 log5(y) since only x is to the power of 5 not y

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Hope this is what you were looking for and helps you! Have a nice day/night :)

5 0

2 years ago