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Taya2010 [7]
3 years ago
11

Answer each question and explain your reasoning.How long is 75% of 60 minutes?​

Mathematics
2 answers:
uysha [10]3 years ago
5 0

Answer:

45 minutes

Step-by-step explanation:

75% is the same as \frac{3}{4}. This means that we can multiply 60 by  \frac{3}{4} to find 75% of 60.

60*\frac{3}{4} \\\\\frac{180}{4} \\\\\frac{90}{2}\\\\45

Irina18 [472]3 years ago
4 0

Answer:

45 minutes

Step-by-step explanation:

Of means multiply

75% * 60

Change to a decimal

.75 * 60

45

45 minutes

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can someone help me figure out how to solve this without a protractor or anything if possible? I have issues with focusing and i
Oksanka [162]

Answer:

C. Equilateral

Step-by-step explanation:

Every pair has equal angle

6 0
2 years ago
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What is the value of sinθ given that (3, −7) is a point on the terminal side of θ ? −758√58 758√58 358√58 −358√58?
Svetach [21]

Answer:

\boxed{\sin(\theta)=-\frac{7}{58}\sqrt{58}}

Step-by-step explanation

The given point (3,-7) tells us that the terminal side of \theta is in the fourth quadrant.


From the diagram in the attachment,

We can use the Pythagoras Theorem to find the length of the hypotenuse of the right triangle.

Let the hypotenuse be h\: units. Then,

h^2=7^2+3^2


h^2=49+9


h^2=58


\Rightarrow h=\sqrt{58}


Now we use the sine ratio;


\sin(\theta)=\frac{Opposite}{Hypotenuse}.


But since the terminal side of \theta is in the fourth quadrant, the sine ratio must be negative.


This implies that;


\sin(\theta)=-\frac{7}{\sqrt{58}}.


We rationalize the denominator to get;


\sin(\theta)=-\frac{7}{58}\sqrt{58}.




3 0
3 years ago
I really need help with Geometry​
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Ramon earns $1,780 each month and pays $53.30 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning
Elis [28]

Answer:

  • 3.0%

Step-by-step explanation:

  • Ramon earns $1,780
  • Ramon pays $53.30 on electricity

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3 years ago
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Need help with trig problem in pic
Sidana [21]

Answer:

a) cos(\alpha)=-\frac{3}{5}\\

b)  \sin(\beta)= \frac{\sqrt{3} }{2}

c) \frac{4+3\sqrt{3} }{10}\\

d)  \alpha\approx 53.1^o

Step-by-step explanation:

a) The problem tells us that angle \alpha is in the second quadrant. We know that in that quadrant the cosine is negative.

We can use the Pythagorean identity:

tan^2(\alpha)+1=sec^2(\alpha)\\(-\frac{4}{3})^2 +1=sec^2(\alpha)\\sec^2(\alpha)=\frac{16}{9} +1\\sec^2(\alpha)=\frac{25}{9} \\sec(\alpha) =+/- \frac{5}{3}\\cos(\alpha)=+/- \frac{3}{5}

Where we have used that the secant of an angle is the reciprocal of the cos of the angle.

Since we know that the cosine must be negative because the angle is in the second quadrant, then we take the negative answer:

cos(\alpha)=-\frac{3}{5}

b) This angle is in the first quadrant (where the sine function is positive. They give us the value of the cosine of the angle, so we can use the Pythagorean identity to find the value of the sine of that angle:

cos (\beta)=\frac{1}{2} \\\\sin^2(\beta)=1-cos^2(\beta)\\sin^2(\beta)=1-\frac{1}{4} \\\\sin^2(\beta)=\frac{3}{4} \\sin(\beta)=+/- \frac{\sqrt{3} }{2} \\sin(\beta)= \frac{\sqrt{3} }{2}

where we took the positive value, since we know that the angle is in the first quadrant.

c) We can now find sin(\alpha -\beta) by using the identity:

sin(\alpha -\beta)=sin(\alpha)\,cos(\beta)-cos(\alpha)\,sin(\beta)\\

Notice that we need to find sin(\alpha), which we do via the Pythagorean identity and knowing the value of the cosine found in part a) above:

sin(\alpha)=\sqrt{1-cos^2(\alpha)} \\sin(\alpha)=\sqrt{1-\frac{9}{25} )} \\sin(\alpha)=\sqrt{\frac{16}{25} )} \\sin(\alpha)=\frac{4}{5}

Then:

sin(\alpha -\beta)=\frac{4}{5}\,\frac{1}{2} -(-\frac{3}{5}) \,\frac{\sqrt{3} }{2} \\sin(\alpha -\beta)=\frac{2}{5}+\frac{3\sqrt{3} }{10}=\frac{4+3\sqrt{3} }{10}

d)

Since sin(\alpha)=\frac{4}{5}

then  \alpha=arcsin(\frac{4}{5} )\approx 53.1^o

4 0
3 years ago
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