All categories

3 years ago

Segment AX and Segment EX are secant segments that intersect at point X. What is the length of ED? a. 1 b. 3 c. 6 d. 9

Mathematics

1 answer:

suter [353]3 years ago

6 0

Answer:

B. 3

Step-by-step explanation:

We can use secant theorem.

AX × BX = EX × DX

AX = 7 + 2 = 9

9 × 2 = (3 + x) × 3

18 = 9 + 3x

18 - 9 = 3x

9 = 3x

x = 9/3 = 3

The length of ED is 3 units.

You might be interested in

I need help with this question please

Elza [17]

The changes in Z would be = 6.1× 10^-4.

<h3>Calculation of the unknown value</h3>

Z = Sin (x³ +y³)

Where X = 0.3

y = 0.2

Z= Sin ( 0.3³ + 0.2³)

Z= Sin ( 0.027 + 0.008)

Z= Sin ( 0.035)

Z= 6.1× 10^-4

Therefore, the changes in Z would be = 6.1× 10^-4.

Learn more about multiplication here:

brainly.com/question/10873737

#SPJ1

5 0

1 year ago

HELPPPPPPPPPPPPPPPPPPPP

otez555 [7]

The answer is A(45) = -211

3 0

3 years ago

Gregory brought 11 pumpkins to school for pumpkin-carving contest. Each pumpkin

Zigmanuir [339]

Answer:

Step-by-step explanation:

I need help too

5 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$