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3 years ago

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Find the value of ×

x - 4) = 14" alt="3x + 2(x - 4) = 14" align="absmiddle" class="latex-formula">

1 answer:

sasho [114]3 years ago

4 0

Answer:

x = 22/5

Step-by-step explanation:

3x+2(x-4) = 14

Distribute

3x+2x -8 = 14

5x - 8 = 14

Add 8 to each side

5x-8+8 = 14+8

5x = 22

Divide by 5

5x/5 = 22/5

x = 22/5

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You need to solve a system of equations. You decide to use the elimination method. Which of these is not allowed? 3x-2y=7 equati

svetlana [45]

Answer:

x = 31/9 and y = 5/3

Step-by-step explanation:

It is given that,

3x - 2y = 7 -----(1)

3x + 4y = 17 ----(2)

<u>To find the solution by elimination method</u>

Step 1: Subtract eq(2) from eq(1)

3x - 2y = 7 -----(1)

<u> 3x + 4y = 17 </u>----(2)

0 - 6y = -10

6y = 10

y = 10/6 = 5/3

Step 2: Substitute the value of y in eq (1)

3x - 2y = 7 -----(1)

3x - 2*(5/3) = 7

3x = 7 + 10/3

3x = 31/3

x = 31/9

Therefore x = 31/9 and y = 5/3

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3 years ago

Read 2 more answers

Pam’s grandfather has a garden that measures 4 feet by 6 feet. How much will the area be increased if he doubles the length and

ExtremeBDS [4]

Answer:

The area will be increased by 72 feet.

Step-by-step explanation:

4 x 6 = 24

Now we have to double those lengths.

We know that 4 x 2 is 8 and 6 x 2 is 12.

So the new equation would be: 8 x 12 = 96

Now we take the original area and subtract it by the new area.

96 - 24 = 72

Hope this helps:)

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2 years ago

Find the price per ounce rounded to the nearest cent: 1 lb 10 oz for $10.98.

Pachacha [2.7K]

Answer is C.) $0.42/oz

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3 years ago

Operations in scientific notation the question is (2.32X10 to the 6 power)(4X10 to the -5power)

olganol [36]

$(2.32\cdot10^6)\cdot(4\cdot10^{-5})=2.32\cdot4\cdot10^1=9.28\cdot10^1$

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3 years ago

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A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : <em>p = </em>0.6

H₁ : <em>p = </em>0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

b)

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago