Answer:
21, 14
Step-by-step explanation:
by dividing 3 from 42 you get 14, and by adding 7 you get 21. And finally by devifing 3 from 21 you get 7 and by adding 7 to 7 you get 14.
Answer:
When solving for x, answer =
When solving for a, answer = 
Step-by-step explanation:
24 + 5x = -x + 6(5a - 4)
Start by multiplying 6 by the values in the parenthesis
24 + 5x = -x + 30a - 24
Add 24 to both sides of the equation
48 + 5x = -x + 30a
Add 1x to both sides of the equation
48 + 6x = 30a
Subtract 48 from both sides of the equation
6x = 30a - 48
Divide both sides of the equation by 6
x = 5a - 8 (Answer when solving for x)
Add 8 to both sides of the equation
x + 8 = 5a
Divide both sides of the equation by 5
a = 1/5x + 8/5 (Answer when solving for a)
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When solving for x, answer =
When solving for a, answer = 
Hope this helps :)
I hope this helps you
12x/2+24/2
6x+12
-6 ( -x-2)
Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]