Enter the range of values for x: B 15 2x - 10 C 48° A 18 5

A car travel 252 mile on 9 gallons of gasoline. How many gallons of gas will it need to go 140 miles

spin [16.1K]

Answer:

5

Step-by-step explanation:

It runs 28 mpg. Divide 140 by 28 to get 5

8 0

3 years ago

Write an equation of the line that passes through the point (3,0) and has the slope, m = -2.

kenny6666 [7]

The equation of a line is Y=mx+b
You know that the slope is -2 and the slope is 'm' so sub it into the equation.
Y=-2x+b
To have an equation of a line you need the 'b' or 'y' intercept and the slope.
This means you have to find the 'b' because you already know the slope which is -2. To find the 'b' you have to sub in the coordinates and then solve for 'b'
Y=-2x+b
(x,y)
(3,0)
0=-2(3)+b
0=-6+b
6=b
Therefore the equation of the line is Y=-2x+6

6 0

4 years ago

which of the following is the most reasonable estimate for the number of calories in one serving of milk? in one-half serving of

MatroZZZ [7]

Answer:

C. between 80 and 90

Step-by-step explanation:

430/5=86

4 0

3 years ago

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

8 0

3 years ago

Read 2 more answers

Change to a decimal. Round to hundredths if necessary. 1 5/8

Mrrafil [7]

Step-by-step explanation:

1 5/8 cam be written as 13/8

now,

13/8 = 1.625

after rounding it in hundred so,

it's is 1.63

HOPE THIS HELPS YOU !