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Margarita [4]
3 years ago
10

How do you solve algebraically 8x^2=18

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
That would be
x =  + \frac{ \sqrt[]{3} }{ \sqrt[]{2} }
BTW the plus sign is supposed to have this sign underneath it _
Good luck.
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an apartment complex contains 200 apartments , of these , x are 3-room apartments, and the others are 4-room apartments . how ma
Elina [12.6K]

Answer:

(800-x)\ rooms

Step-by-step explanation:

Let

x ----> 3-room apartments

200-x ----> 4-room apartments

we know that

To find out how many rooms are there in the complex, sum the number of 3-room apartments multiplied by 3 plus the number of 4-room apartments multiplied by 4

so

3x+4(200-x)

Apply distributive property

3x+800-4x

Combine like terms

(800-x)\ rooms

4 0
3 years ago
In 2009, Usain Bolt set the world record for sprinting 100m in approximately 9 3/5 seconds.
Hitman42 [59]

Answer:

10 5/12 is the answer, hope this helps

4 0
3 years ago
Is 7/45 a repeating or terminating
timurjin [86]

I believe that  7/45 is a repeating decimal

8 0
3 years ago
Producers will make 1000 refrigerators available when the unit price is $280.00. At a unit price of $400, 5000 refrigerators wil
Kobotan [32]

Answer:

For linear equations we use:

p=mx+b   ------  (1)

Now we have the following coordinates:

(x1,p1)= (1000,280) and (x2, p2)=(5000,400)

First we need slope (m)

m= (400-280)/(5000-1000)

= 120/4000=0.03

Now we will plug the value of m in the first equation

280=0.03(1000)+b

=> 280=30+b

=> b = 250

Now plug into p=mx+b using only m=0.03 and b=250

p=0.03x+250

When the unit price is $440, we can plug in 440 in for p;

440=0.03x+250

=> 0.03x=440-250

=> 0.03x=190

=> x = 6333 refrigerators

The lowest price at which  a refrigerator will be marketed, we can find this by plugging x = 0 in p=mx+b.

p=0.03(0)+250

=> p = $250

6 0
3 years ago
Factor x squared-6x+3x-18 by grouping ​
Sindrei [870]

Answer:

(x - 6)(x + 3)

Step-by-step explanation:

Given

x² - 6x + 3x - 18 ( factor the first/second and third/fourth terms )

= x(x - 6) + 3(x - 6) ← factor out (x - 6) from each term

= (x - 6)(x + 3)

6 0
3 years ago
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